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5x^2-5.56x+1.4=0
a = 5; b = -5.56; c = +1.4;
Δ = b2-4ac
Δ = -5.562-4·5·1.4
Δ = 2.9136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.56)-\sqrt{2.9136}}{2*5}=\frac{5.56-\sqrt{2.9136}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.56)+\sqrt{2.9136}}{2*5}=\frac{5.56+\sqrt{2.9136}}{10} $
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